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Example 2 |
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| Explanation
Objectives
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A contestant wins $4000 on the "Wheel
of Wealth" game show. She invests part of her winnings in an account which
earns 8% annual interest. She places the rest of the money in an account
which earns 6% annual interest. After one year the total interest earned
from both accounts is $300. How much money was in each account originally?
Hint: Let x = amount invested at 8 % Solution Step 1: Identify the desired variable.
The hint tells us to use the variable "x" to represent the That is, Step 2: Identify the known relationships in the problem.
The problem statement tells us that the total money
Since we are representing the amount
in the 8 % account That is, We will also need the formula: (money invested)(annual
interest rate)(time) = interest earned Vocabulary & notation: "Principal" =money invested = P annual interest rate = r time = t interest earned = I Note: You MUST write the interest rate as a DECIMAL! 8 % = 8/100 = 0.08 6% = 6/100 =0 .06 We can construct a table to help us organize the given information.
Step 3: Construct a one variable
equation which fits the known The problem statement tells us that the total interest earned from the two accounts is $300.
Using the entires from the "interest earned" column in our Total Interest earned = $300 (0.08)(x) + (0.06)(4000 - x) = 300 Step 4: Solve the equation. Solving for x, we get 0.08x + 240 - 0.06x = 300 0.02x = 60 x = (60)/(0.02) = 3000 Step 5: Use the solution from
Step 4 to answer the question(s) Plugging the value x = 3000 into
our table, we see that the contestant invested $3000 at 8% and $1000 at
6 %. Special Note: Be sure to check that your final answers "make sense" in the context of the original problem. In this problem, for example, our equation needed to yield a non-negative number for the value of "x". That is, it wouldn't "make sense" for the contestant to have invested a negative amount of money. |