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Applications of Linear Equations
Example 2
Explanation
 

Objectives 


Examples

     
    A contestant wins $4000 on the "Wheel of Wealth" game show. She invests part of her winnings in an account which earns 8% annual interest. She places the rest of the money in an account which earns 6% annual interest. After one year the total interest earned from both accounts is $300. How much money was in each account originally?

    Hint:  Let x = amount invested at 8 %

    Solution
        Our goal is to construct a one-variable equation which 
        matches the given information.

        Step 1: Identify the desired variable.

            The hint tells us to use the variable "x" to represent the
            amount invested at 8 % interest.

            That is,

    x = amount invested at 8 %

        Step 2: Identify the known relationships in the problem.

            The problem statement tells us that the total money
            invested is $4000.

         Since we are representing the amount in the 8 % account
            by the variable "x", we can represent the amount of money
            in the 6 % account by the expression "4000 - x."

            That is,

    4000 - x = amount invested at 6 %

           We will also need the formula:

    (money invested)(annual interest rate)(time) = interest earned



    Vocabulary & notation: 

            "Principal" =money invested = P

             annual interest rate = r

             time = t

             interest earned = I

    Note:  You MUST write the interest rate as a DECIMAL!

    8 % = 8/100 = 0.08

    6% = 6/100 =0 .06



            We can construct a table to help us organize the given
            information.
     

    r t I
     8 % account 0.08  1 (0.08)(x)
    6 % account 4000 - x 0.06 1 (0.06)(4000 - x)

    Step 3: Construct a one variable equation which fits the known
                  relationships in the problem.

            The problem statement tells us that the total interest earned from the two accounts is $300.

            Using the entires from the "interest earned" column in our
            table, we have the equation:

    Total Interest earned = $300

    (0.08)(x) + (0.06)(4000 - x)  = 300

    Step 4: Solve the equation.

             Solving for x, we get

    0.08x + 240 - 0.06x  = 300

    0.02x = 60

    x = (60)/(0.02) = 3000

    Step 5: Use the solution from Step 4 to answer the question(s)
                  posed in the original problem. 

    Plugging the value x = 3000 into our table, we see that the contestant invested $3000 at 8% and $1000 at 6 %.



    Special Note: Be sure to check that your final answers "make sense" in the context of the original problem. 

    In this problem, for example, our equation needed to yield a non-negative number for the value of "x". 

    That is, it wouldn't "make sense" for the contestant to have invested a negative amount of money.

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